2x^2+17x+45=3x-5

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Solution for 2x^2+17x+45=3x-5 equation: 



2x^2+17x+45=3x-5

We move all terms to the left:

2x^2+17x+45-(3x-5)=0

We get rid of parentheses

2x^2+17x-3x+5+45=0

We add all the numbers together, and all the variables

2x^2+14x+50=0

a = 2; b = 14; c = +50;
Δ = b2-4ac
Δ = 142-4·2·50
Δ = -204
Delta is less than zero, so there is no solution for the equation

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